How far will a freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/

I need not only the answer, but how to do it so I know how to do it. In an esay to understand explanation please. Thank you.How far will a freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/
Use kinetic and potential energy





mgh = mv^2 / 2


h = v^2 / (2g)


= 10^2 / (2*9.81)


= 5.1 m


or 5 m if you use g = 10 m/s^2How far will a freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/
This is a two-step procedure. For a ';rest'; position drop,


First, v= a*t, you have v and a, so you find t (about 1 second)


Then x = (a/2)t^2. You have a and t, so find x.


(about 5 meters)
Vf^2 = 2ad + Vi^2





Vf = final velocity (10m/s)


a = accelertion (9.8m/s^2)


d = displacement


Vi = initial velocity (0m/s)





(10)^2 = 2(9.8)d + 0


100 = 19.6d


d =~ 5.1m